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10x^2+5x-24=0
a = 10; b = 5; c = -24;
Δ = b2-4ac
Δ = 52-4·10·(-24)
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{985}}{2*10}=\frac{-5-\sqrt{985}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{985}}{2*10}=\frac{-5+\sqrt{985}}{20} $
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